In C++, what is the best way for me to read a users string input....?

How can I take a user's first and last name with std::cin and print it back out with only using one variable? I'm new to C++ but have an extensive understanding of Java and general programing. Here is my code:





#include %26lt;iostream%26gt;


#include %26lt;string%26gt;





using namespace std;





int main() {


string user;





cout %26lt;%26lt; "Please enter your name: ";


cin %26gt;%26gt; user;


cout %26lt;%26lt; "\nWelcome " %26lt;%26lt; user %26lt;%26lt; "!" %26lt;%26lt; endl;





system("pause");


return 0;


}





The problem is that this program only prints the first string entered.

In C++, what is the best way for me to read a users string input....?
The problem is cin terminates the string when it encounters whitespace. So you have to use another method....








#include %26lt;iostream%26gt;


#include %26lt;string%26gt;





using namespace std;





int main() {





string user;














cout %26lt;%26lt; "Please enter your name: ";





// this will allow you to input spaces


getline(cin,user);





cout %26lt;%26lt; "\nWelcome " %26lt;%26lt; user %26lt;%26lt; "!" %26lt;%26lt; endl;








system("pause");


return 0;





}
Reply:Cause you only input one string and output the same thing. Concatenate strings.


In java, cause I am forgetting C++ at the moment





String fullName = fName +lName;


System.out.println(fullName);


OR


System.out.println(flName + " " + lName);
Reply:Using this








#include %26lt;iostream%26gt;








using namespace std;





int main() {





char buffer[100]; //buffer size 100





cout %26lt;%26lt; "Please enter your name: ";


cin.getline(buffer,101 ); //terminate input when carriage return hit, can specify the terminate charater in the third argument by default it's \n





string user = buffer;


//might want to do tokenizing here if you have multiple input


cout %26lt;%26lt; "\nWelcome " %26lt;%26lt; user %26lt;%26lt; "!" %26lt;%26lt; endl;





system("pause");


return 0;


}