How do you convert a long to a string in C? Thanks?

Yes, there is one, clean function available in the C standard library for this purpose....available in every C compiler I've used/owned.





From MSVC++ online help:


--------------------------------------...


Convert a long integer to a string:


char *_ltoa( long value, char *string, int radix );





Return Value: returns a pointer to string. There is no error return.





Parameters:


value -%26gt; Number to be converted


string -%26gt; String result


radix -%26gt; Base of value





Remarks: The _ltoa function converts the digits of value to a null-terminated character string and stores the result (up to 33 bytes) in string. The radix argument specifies the base of value, which must be in the range 2 – 36. If radix equals 10 and value is negative, the first character of the stored string is the minus sign (–).








Example:


/* ITOA.C: This program converts integers of various


* sizes to strings in various radixes.


*/





#include %26lt;stdlib.h%26gt;


#include %26lt;stdio.h%26gt;





void main( void )


{


char buffer[20];


int i = 3445;


long l = -344115L;


unsigned long ul = 1234567890UL;





_itoa( i, buffer, 10 );


printf( "String of integer %d (radix 10): %s\n", i, buffer );


_itoa( i, buffer, 16 );


printf( "String of integer %d (radix 16): 0x%s\n", i, buffer );


_itoa( i, buffer, 2 );


printf( "String of integer %d (radix 2): %s\n", i, buffer );





_ltoa( l, buffer, 16 );


printf( "String of long int %ld (radix 16): 0x%s\n", l,


buffer );





_ultoa( ul, buffer, 16 );


printf( "String of unsigned long %lu (radix 16): 0x%s\n", ul,


buffer );


}








Output:


String of integer 3445 (radix 10): 3445


String of integer 3445 (radix 16): 0xd75


String of integer 3445 (radix 2): 110101110101


String of long int -344115 (radix 16): 0xfffabfcd


String of unsigned long 1234567890 (radix 16): 0x499602d2

How do you convert a long to a string in C? Thanks?
i would use sprintf:





char buffer[20];


sprintf(buffer, "%u", value);





(you can also use snprintf, it's better but not available for every compiler).
Reply:Cast the long as a string





long i;





cout%26lt;%26lt;(string)i;
Reply:I think you can just type cast this. Try:





long toConv = 101;


string longString = (string) toBeConv;





longString is now a string that equals '101'





Sorted.
Reply:i am not sure if there is such a function...





although i know of its reverse (string to a long) through strtol(); and atol();





why not try to make the string variable assume the value of the long variable like this...





long X;


string Y;





Y = X;





but i am not sure if this works... i have studied C and C++ 7yrs ago...





:)

imperial