How to pass two dimensional array of string in 'c' ?

i just wants to know to how to pass two dimensiobnal array of string to a function


say:





main()


{


char a[][]={"nitish","abhik",


"vikas"};





sort(%26lt;?%26gt;);





}





void sort(%26lt;?%26gt;)


{


}





i wants to pass array a[][] to the function sort





what are the arguments of sort





simply what is "?"


Thanks

How to pass two dimensional array of string in 'c' ?
No need to pass pointers, do this instead.





#include %26lt;stdio.h%26gt;





void function_that_gets_array(char* theArr[]) {


int i=0;


for (i=0; i %26lt; 3; i++) {


printf("Element %s\n",theArr[i]);


}


return;


}








int main(int argc, char* argv) {


char* a[] = {"one","two","three"};


function_that_gets_array(a);


return 1;


}





------


This example compiles, and works.





gubatrons-macbook-pro:/tmp gubatron$ gcc sample.c -o sample


gubatrons-macbook-pro:/tmp gubatron$ ./sample


Element one


Element two


Element three





-----





The trick is not to use a[][], but char* a[];
Reply:you need to define the number of columns in the array to be passed.





for example:


a[][] = {...};


sort(a); //sort(a) will get an error





sort(a[?]);


// these will be valid but you need to specify the ? so that the compiler knows how the array should be oriented. (simply put the compiler cannot know where the rows ends and the columns ends because it does not know the dimensions)





or you could just pass a pointer to a 2D array like this:





char *ptr_2D;


char a[][] = {...};


ptr_2D = a;


//im not sure about this, you may need to include the dimensions as well


sort(char*);


sort(ptr_2D);
Reply:using pointers...


-----------------------


function declaration.


sort(char * );





function definition


sort(char *arr)