I need to create a C++ program which will analyze a sentence written in the code and print the longest words?

Say the sentence was "There's the spoons pass me one" I would like the program to print both "There's" as its the longest word with an " ' " and "spoons" because its the longest word.





I am trying to work it out using strings and arrays.





Im using Visuall Studio 2005 c++.





Also how can I get the program to tell me how many of 1 letter is in the whole sentence.

I need to create a C++ program which will analyze a sentence written in the code and print the longest words?
Here is a gift.





#include %26lt;iostream%26gt;


#include %26lt;string%26gt;


#include %26lt;vector%26gt;





using namespace std;





int findLetter(const string%26amp; str, const char letter)


{


size_t pos = 0;


int count = 0;





do


{


pos = str.find(letter, pos);


if (pos != string::npos)


{


count++;


pos++;


}





} while (pos != string::npos);





return(count);


}








void parseWords(vector%26lt;string%26gt; %26amp;a, string str)


{


size_t pos = 0;


size_t start = 0;


string tempStr;





do


{


pos = str.find(' ', start);


if (pos != string::npos)


{


tempStr = str.substr(start, pos - start);


pos++;


start = pos;


}


else


{


if (start != string::npos)


{


tempStr = str.substr(start);


}


}





a.push_back(tempStr);





} while (pos != string::npos);





}














int main(int argc, char *argv[])


{


const string sentence("There's the spoons pass me one");





char letter;





//find requested letter





cout %26lt;%26lt; "Enter letter to find in sentence: ";


cin %26gt;%26gt; letter;


cout %26lt;%26lt; letter %26lt;%26lt; " occurs: " %26lt;%26lt; findLetter(sentence, letter) %26lt;%26lt; " times." %26lt;%26lt; endl;





//load array of words in sentence





vector%26lt;string%26gt; array;





parseWords(array, sentence);





//find longest word





int largestSize = 0;


string largestStr;





vector%26lt;string%26gt;::iterator pos = array.begin();


vector%26lt;string%26gt;::iterator end = array.end();





for (; pos != end; ++pos)


{


if (pos-%26gt;length() %26gt; largestSize)


{


largestSize = pos-%26gt;length();


largestStr = *pos;


}


}





cout %26lt;%26lt; "Largest word was \"" %26lt;%26lt; largestStr %26lt;%26lt; "\" with a size of " %26lt;%26lt; largestSize %26lt;%26lt; endl;


}
Reply:the one letter of each is easy store the string in an array and go through it letter by letter until you reach the end, have a switch set up example





get the letter put in x





switch (x)





case (a) :





case (b) :








for the first part count letters until white space, store location thats longest somewhere, index through whole sentense if longer replace if not stay the same at the end have a pointer pointing to the beginning of the longest word and print it out or whatever








should get you started think correctly