|Block A|----|Block B|----|Block C|-----%26gt; F
3 blocks are pulled along a frictionless surface by force F, a horizontal force.
All 3 blocks have the same mass of 0.4 kg and the tension of the string between Blocks B and C is 3 N.
From this, is the tension of the string between A and B 6 N?
How do I find force F? Apparently I first need the acceleration of B then the entire system, so
Is the acceleration of B
F=ma
3=0.4(a)
a=3/0.4
a=7.5?
How do I find the acceleration of the total system after this?
Could someone explain?
Pulling Three Blocks Connected By Strings?
If the force between b and c is 3N, then the force between A and B would be half that , i.e 1.5 N. Force F at Block C would be 3 * 1.5 = 4.5 N.
Acceleration of all 3 blocks is 4.5 = (3*0.4) a
a = 4.5 / 1.2 = 3.75 m/s
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